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MHT CET 2023 (10 May, Shift 2) · Viscosity & Stokes' Law

Viscosity & Stokes' Law question from MHT CET 2023 (10 May, Shift 2)

Q14MHT CET 2023 · 10 MAY · SHIFT 2Medium

Viscosity & Stokes' Law

A metal sphere of mass 'mm' and density 'σ1\sigma_1' falls with terminal velocity through a container containing liquid. The density of liquid is 'σ2\sigma_2 '. The viscous force acting on the sphere is

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Answer: (c)

  1. At terminal velocity: Fv=mg−BF_v = mg - B.
  2. B=Vσ2g=mσ1σ2gB = V\sigma_2 g = \frac{m}{\sigma_1}\sigma_2 g
  3. Fv=mg(1−σ2σ1)F_v = mg\left(1 - \frac{\sigma_2}{\sigma_1}\right)
  4. So the answer is (c).
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