A metal surface of work function 1.13 eV is irradiated with light of wavelength 310 nm. The retarding potential required to stop the escape of photoelectrons is [Take hc/e = 1240 × 10⁻⁹ SI units] (a) 1.13 V (b) 2.87 V (c) 3.97 V (d) 4.23 V

Answer: (b). Photon energy in eV: E = (hc/e)/(λ) = 1240 × 10⁻⁹310 × 10⁻⁹ = 4 eV eV₀ = E - φ = 4 - 1.13 = 2.87 eV So the answer is (b) 2.87 V.

A metal surface of work function 1.13 eV is irradiated with light of… | MHT CET 2023 (11 May, Shift 2)

Q75MHT CET 2023 · 11 MAY · SHIFT 2Easy

Photoelectric Effect: Einstein's Equation

A metal surface of work function $1.13\text{ eV}$ is irradiated with light of wavelength $310\text{ nm}$ . The retarding potential required to stop the escape of photoelectrons is [Take $\frac{hc}{e} = 1240 \times 10^{-9}\text{ SI}$ units]

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Answer: (b)

Photon energy in eV: $E = \frac{hc/e}{\lambda} = \frac{1240 \times 10^{-9}}{310 \times 10^{-9}} = 4\text{ eV}$
$eV_0 = E - \phi = 4 - 1.13 = 2.87\text{ eV}$
So the answer is (b) 2.87 V.

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