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JEE Main 2022 (27 Jun, Shift 2) · Motional EMF

Motional EMF question from JEE Main 2022 (27 Jun, Shift 2)

Q33JEE Main 2022 · 27 JUN · SHIFT 2Medium

Motional EMF

A metallic rod of length 20 cm is placed in North-South direction and is moved at a constant speed of 20 m/s towards East. The horizontal component of the Earth's magnetic field at that place is 4 ×\times 10−-3 T and the angle of dip is 45∘^{\circ}. The emf induced in the rod is ___________ mV.

Numerical answer type. Work it out, then open the answer.

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Answer: 16

  1. Rod N–S moving east: BHB_H (north) is along the rod, so it gives no emf; only BVB_V is cut.
  2. BV=BHtan⁡δ=4×10−3×tan⁡45∘=4×10−3B_V = B_H\tan\delta = 4\times10^{-3} \times \tan45^\circ = 4\times10^{-3} T.
  3. ε=BVlv=4×10−3×0.2×20=0.016\varepsilon = B_V l v = 4\times10^{-3} \times 0.2 \times 20 = 0.016 V
  4. Answer: 1616 mV.
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