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JEE Main 2023 (24 Jan, Shift 2) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from JEE Main 2023 (24 Jan, Shift 2)

Q19JEE Main 2023 · 24 JAN · SHIFT 2Easy

Rotating Conductors & AC Generator

A metallic rod of length 'L' is rotated with an angular speed of 'ω\omega' normal to a uniform magnetic field 'B' about an axis passing through one end of rod as shown in figure. The induced emf will be:

Figure

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Answer: (b)

  1. Each element dxdx at distance xx has speed ωx\omega x: de=Bωx dxde = B\omega x\,dx.
  2. e=∫0LBωx dx=12BL2ωe = \int_0^L B\omega x\,dx = \tfrac{1}{2}BL^2\omega
  3. So the answer is (b) 12BL2ω\tfrac{1}{2}BL^2\omega.
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