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MHT CET 2021 (23 Sep, Shift 2) · Torque, Couple & Equilibrium of Rigid Bodies

Torque, Couple & Equilibrium of Rigid Bodies question from MHT CET 2021 (23 Sep, Shift 2)

Q24MHT CET 2021 · 23 SEP · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies

A metre scale is supported on a wedge at its centre of gravity. A body of weight 'w' is suspended from the 20 cm20\text{ cm} mark and another weight of 25 gram is suspended from 74 cm74\text{ cm} mark to balance it and the metre scale remains perfectly horizontal. Neglecting the weight of the metre scale, the weight of the body is

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Answer: (a)

  1. Pivot at 50 cm (centre of gravity). Take moments about it.
  2. w(50−20)=25(74−50)w(50-20) = 25(74-50)
  3. 30w=600⇒w=2030w = 600 \Rightarrow w = 20 gram-wt
  4. So the answer is (a).
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