A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is λ, calculate the change of microscope's resolving power due to oil and choose the correct option. (a) Resolving power will be 1/4 in the oil than it was in the air. (b) Resolving power will be twice in the oil than it was in the air. (c) Resolving power will be four times in the oil than it was in the air. (d) Resolving power will be 1/2 in the oil than it was in the air.

Answer: (b). Resolving power of a microscope: RP = (2nsin θ)/(λ). Changing n from 1 to 2 doubles RP. So the answer is (b) twice in oil.

A microscope was initially placed in air (refractive index 1). It is… | JEE Main 2022 (27 Jul, Shift 1)

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Optical Instruments & the Eye

A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is $\lambda$ , calculate the change of microscope's resolving power due to oil and choose the correct option.

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Answer: (b)

Resolving power of a microscope: $RP = \dfrac{2n\sin\theta}{\lambda}$ .
Changing $n$ from 1 to 2 doubles $RP$ .
So the answer is (b) twice in oil.

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