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JEE Main 2024 (1 Feb, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from JEE Main 2024 (1 Feb, Shift 2)

Q34JEE Main 2024 · 1 FEB · SHIFT 2Medium

Diffraction at a Single Slit

A microwave of wavelength $2.0\text{ cm}$ falls normally on a slit of width $4.0\text{ cm}$ . The angular spread of the central maxima of the diffraction pattern obtained on a screen $1.5\text{ m}$ away from the slit, will be:

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Answer: (a)

First minimum: $a\sin\theta = \lambda \Rightarrow \sin\theta = \dfrac{2.0}{4.0} = \dfrac{1}{2}$
$\theta = 30^\circ$ on each side of the centre.
Angular spread $= 2\theta$ . So the answer is (a) $60^\circ$ .

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