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MHT CET 2020 (19 Oct, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2020 (19 Oct, Shift 2)

Q134MHT CET 2020 · 19 OCT · SHIFT 2Easy

Kirchhoff's Laws & Measuring Instruments

A milliammeter of resistance $40\ \Omega$ has a range $0 - 30\text{ mA}$ . What will be the resistance used in series to convert it into voltmeter of range $0 - 15\text{ V}$ ?

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Answer: (a)

Series resistance $R = \frac{V}{I_g} - G$ .
$R = \frac{15}{30 \times 10^{-3}} - 40 = 500 - 40 = 460\ \Omega$
So the answer is (a) $460\ \Omega$ .

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