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MHT CET 2023 (13 May, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from MHT CET 2023 (13 May, Shift 2)

Q56MHT CET 2023 · 13 MAY · SHIFT 2Easy

Acceleration Due to Gravity

A mine is located at depth $R/3$ below earth's surface. The acceleration due to gravity at that depth in mine is ( $R =$ radius of earth, $g =$ acceleration due to gravity)

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Answer: (c)

$g_d = g\left(1 - \frac{d}{R}\right)$ with $d = \frac{R}{3}$ .
$g_d = g\left(1 - \frac{1}{3}\right) = \frac{2g}{3}$
So the answer is (c) $\frac{2g}{3}$ .

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