A mixture of carbon dioxide and oxygen has volume 8310 cm3… | JEE Main 2026 (2 Apr, Shift 2)

Q15JEE Main 2026 · 2 APR · SHIFT 2Medium

Gas Laws & Ideal Gas Equation

A mixture of carbon dioxide and oxygen has volume 8310 cm3, temperature 300 K, pressure 100 kPa and mass 13.2 g. The number of moles of carbon dioxide and oxygen gases in the mixture respectively are ______.

(Assume both carbon dioxide and oxygen gases behave like ideal gases) [R = 8.31 J/mol K]

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Answer: (c)

Total moles $n = \frac{PV}{RT} = \frac{10^5 \times 8.31 \times 10^{-3}}{8.31 \times 300} = \frac{1}{3} \approx 0.333$ mol.
Let $x$ = moles of CO₂, $y$ = moles of O₂: $x + y = \frac{1}{3}$ and $44x + 32y = 13.2$ .
$44x + 32\left(\frac{1}{3} - x\right) = 13.2 \Rightarrow 12x = 2.53 \Rightarrow x \approx 0.21$ , $y \approx 0.12$ .
So the answer is (c) 0.21 and 0.12.

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