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JEE Main 2021 (31 Aug, Shift 2) · Gas Laws & Ideal Gas Equation

Gas Laws & Ideal Gas Equation question from JEE Main 2021 (31 Aug, Shift 2)

Q60JEE Main 2021 · 31 AUG · SHIFT 2Medium

Gas Laws & Ideal Gas Equation

A mixture of hydrogen and oxygen has volume 500 cm3, temperature 300 K, pressure 400 kPa and mass 0.76 g. The ratio of masses of oxygen to hydrogen will be :-

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Answer: (c)

  1. Total moles n=PVRT=4×105×5×10−48.31×300≈0.080n = \frac{PV}{RT} = \frac{4 \times 10^5 \times 5 \times 10^{-4}}{8.31 \times 300} \approx 0.080 mol.
  2. x+y=0.080x + y = 0.080 and 2x+32y=0.762x + 32y = 0.76 give x≈0.06x \approx 0.06 mol H₂, y≈0.02y \approx 0.02 mol O₂.
  3. Masses: H₂ =0.12= 0.12 g, O₂ =0.64= 0.64 g; ratio =0.640.12=163= \frac{0.64}{0.12} = \frac{16}{3}.
  4. So the answer is (c) 16:316 : 3.
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