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NEET 2014 (AIPMT) · Thermodynamic Processes

Thermodynamic Processes question from NEET 2014 (AIPMT)

Q231NEET 2014 · AIPMTMedium

Thermodynamic Processes

A monatomic gas at a pressure P, having a volume V expands isothermally to a volume 2V and then adiabatically to a volume 16V. The final pressure of the gas is (Take γ\gamma = 5/3)

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Answer: (c)

  1. Isothermal V→2VV \to 2V: P1=P2P_1 = \frac{P}{2}.
  2. Adiabatic 2V→16V2V \to 16V: P2=P2(18)5/3=P2×132P_2 = \frac{P}{2}\left(\frac{1}{8}\right)^{5/3} = \frac{P}{2} \times \frac{1}{32}
  3. So the answer is (c) P/64.
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