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MHT CET 2023 (11 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2023 (11 May, Shift 1)

Q156MHT CET 2023 · 11 MAY · SHIFT 1Medium

Thermodynamic Processes

A monoatomic gas at pressure 'PP', having volume 'VV' expands isothermally to a volume '2 V2\,V' and then adiabatically to a volume ' 16 V16\,V'. The final pressure of the gas is (Take γ=5/3\gamma = 5/3)

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Answer: (a)

  1. Isothermal V→2VV \to 2V: P1=P2P_1 = \frac{P}{2}.
  2. Adiabatic 2V→16V2V \to 16V: P2=P2(2V16V)5/3=P2×(18)5/3=P2×132P_2 = \frac{P}{2}\left(\frac{2V}{16V}\right)^{5/3} = \frac{P}{2} \times \left(\frac{1}{8}\right)^{5/3} = \frac{P}{2} \times \frac{1}{32}
  3. P2=P64P_2 = \frac{P}{64}
  4. So the answer is (a) P/64P/64.
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