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MHT CET 2026 (16 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (16 Apr, Shift 1)

Q51MHT CET 2026 · 16 APR · SHIFT 1Difficult

Thermodynamic Processes

A monoatomic gas at pressure P having volume V expands isothermally to a volume 3V and then adiabatically to a volume 81 V. The final pressure of the gas is (γ=5/3\gamma = 5/3).

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Answer: (d)

  1. Isothermal V→3VV \to 3V: P1=P3P_1 = \frac{P}{3}.
  2. Adiabatic 3V→81V3V \to 81V (ratio 27): P2=P3(127)5/3=P3×135P_2 = \frac{P}{3}\left(\frac{1}{27}\right)^{5/3} = \frac{P}{3} \times \frac{1}{3^5}
  3. P2=P36P_2 = \frac{P}{3^6}, so the answer is (d).
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