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MHT CET 2023 (12 May, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2023 (12 May, Shift 2)

Q158MHT CET 2023 · 12 MAY · SHIFT 2Difficult

Thermodynamic Processes

A monoatomic ideal gas initially at temperature 'T1T_1 ' is enclosed in a cylinder fitted with massless, frictionless piston. By releasing the piston suddenly the gas is allowed to expand to adiabatically to a temperature 'T2T_2 '. If 'L1L_1 ' and 'L2L_2' are the lengths of the gas columns before and after expansion respectively, then T2T1\frac{T_2}{T_1} is

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Answer: (c)

  1. Adiabatic, monatomic γ=53\gamma = \frac{5}{3}: TV2/3=TV^{2/3} = constant, and V∝LV \propto L.
  2. T1L12/3=T2L22/3T_1L_1^{2/3} = T_2L_2^{2/3}
  3. T2T1=(L1L2)2/3\frac{T_2}{T_1} = \left(\frac{L_1}{L_2}\right)^{2/3}
  4. So the answer is (c).
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