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MHT CET 2025 (22 Apr, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (22 Apr, Shift 2)

Q91MHT CET 2025 · 22 APR · SHIFT 2Difficult

Thermodynamic Processes

A monoatomic ideal gas, initially at temperature T1T_1 is enclosed in a cylinder fitted with massless, frictionless piston. By releasing the piston suddenly, the gas is allowed to expand adiabatically to a temperature T2T_2. If L1L_1 and L2L_2 are the lengths of the gas columns before and after expansion respectively, then (T2/T1)(T_2/T_1) is given by

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Answer: (c)

  1. Adiabatic, monatomic γ=53\gamma = \frac{5}{3}: TV2/3=TV^{2/3} = constant, and V∝LV \propto L.
  2. T1L12/3=T2L22/3T_1L_1^{2/3} = T_2L_2^{2/3}
  3. T2T1=(L1L2)2/3\frac{T_2}{T_1} = \left(\frac{L_1}{L_2}\right)^{2/3}
  4. So the answer is (c).
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