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MHT CET 2025 (25 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2025 (25 Apr, Shift 1)

Q81MHT CET 2025 · 25 APR · SHIFT 1Medium

Thermodynamic Processes

A monoatomic ideal gas is compressed adiabatically to (127)\left(\frac{1}{27}\right) of its initial volume. If initial temperature of the gas is ' T ' K and final temperature is ' xT ' K, the value of ' x ' is

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Answer: (b)

  1. Adiabatic: TVγ−1=constTV^{\gamma-1} = \text{const}, γ−1=23\gamma - 1 = \frac{2}{3} for a monoatomic gas.
  2. T2=T(V1V2)2/3=T⋅272/3=9TT_2 = T\left(\frac{V_1}{V_2}\right)^{2/3} = T \cdot 27^{2/3} = 9T
  3. So the answer is (b) x=9x = 9.
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