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JEE Main 2019 (11 Jan, Shift 2) · Prism, Dispersion & Scattering

Prism, Dispersion & Scattering question from JEE Main 2019 (11 Jan, Shift 2)

Q73JEE Main 2019 · 11 JAN · SHIFT 2Medium

Prism, Dispersion & Scattering

A monochromatic light is incident at a certain angle on an equilateral triangular prism and suffers minimum deviation. If the refractive index of the material of the prism is 3\sqrt{3}, then the angle of incidence is:

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Answer: (a)

  1. At minimum deviation r1=r2=A2=30∘r_1 = r_2 = \frac{A}{2} = 30^\circ for an equilateral prism.
  2. Snell's law: sin⁡i=μsin⁡r=3×12=32\sin i = \mu \sin r = \sqrt{3}\times\frac{1}{2} = \frac{\sqrt{3}}{2}
  3. So the answer is (a) i=60∘i = 60^\circ.
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