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JEE Main 2025 (3 Apr, Shift 2) · Wave Theory, Wavefronts & Doppler Effect

Wave Theory, Wavefronts & Doppler Effect question from JEE Main 2025 (3 Apr, Shift 2)

Q8JEE Main 2025 · 3 APR · SHIFT 2Easy

Wave Theory, Wavefronts & Doppler Effect

A monochromatic light of frequency 5×1014 Hz5 \times 10^{14}\text{ Hz} travelling through air, is incident on a medium of refractive index ' 2 '. Wavelength of the refracted light will be:

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Answer: (b)

  1. Wavelength in air: λ0=c/ν=3×1085×1014=6×10−7\lambda_0 = c/\nu = \dfrac{3\times10^{8}}{5\times10^{14}} = 6\times10^{-7} m =600= 600 nm.
  2. In the medium: λ=λ0/μ=600/2=300\lambda = \lambda_0/\mu = 600/2 = 300 nm.
  3. So the answer is (b) 300 nm.
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