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JEE Main 2025 (3 Apr, Shift 2) · Electrical Power & Heating Effect

Electrical Power & Heating Effect question from JEE Main 2025 (3 Apr, Shift 2)

Q6JEE Main 2025 · 3 APR · SHIFT 2Easy

Electrical Power & Heating Effect

A motor operating on 100 V draws a current of 1 A. If the efficiency of the motor is 91.6%91.6\%, then the loss of power in units of cal/s\text{cal/s} is

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Answer: (b)

  1. Input power =VI=100×1=100 W= VI = 100 \times 1 = 100\ \text{W}.
  2. Loss =(100−91.6)%×100=8.4 W= (100 - 91.6)\% \times 100 = 8.4\ \text{W}.
  3. In cal/s: 8.44.2=2 cal/s\frac{8.4}{4.2} = 2\ \text{cal/s}.
  4. So the answer is (b) 2.
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