Student Login

Home›Chapters›Current Electricity PYQs›Kirchhoff's Laws & Measuring Instruments›Question 151

JEE Main 2019 (10 Apr, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2019 (10 Apr, Shift 1)

Q151JEE Main 2019 · 10 APR · SHIFT 1Easy

Kirchhoff's Laws & Measuring Instruments

A moving coil galvanometer allows a full scale current of 10–4 A. A series resistance of 2 M $\Omega$ is required to convert the above galvanometer into a voltmeter of range 0-5 V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0-10 mA is:

Show answer and solution

Answer: (d)

For the voltmeter: $I_g(G + R) = 5 \Rightarrow G + R = \frac{5}{10^{-4}} = 5 \times 10^4\ \Omega$ .
With $R = 2\text{ M}\Omega$ this gives $G = 5 \times 10^4 - 2 \times 10^6 < 0$ , which is impossible.
So the data is inconsistent and no option fits: the answer is (d) None of the options are correct.

Report a mistake

More questions on Kirchhoff's Laws & Measuring Instruments

The resistance of a galvanometer is 50 ohm and the maximum current which can be passed…JEE Main 2019 (9 Apr, Shift 2)
A moving coil galvanometer has resistance 50 Ω and it indicates full deflection at 4mA…JEE Main 2019 (9 Apr, Shift 1)
In moving coil galvanometer, strong horse shoe magnet of concave shaped pole pieces is…MHT CET 2019 (2 May, Shift 1)
In the given electrical circuit, which one of the following equations is a correct…MHT CET 2019 (2 May, Shift 2)
The current in 1 Ω resistor in the following circuit isMHT CET 2019 (2 May, Shift 1)
In the given circuit diagram, the currents, I1 = – 0.3 A, I4 = 0.8 A and I5 = 0.4 A, are…JEE Main 2019 (12 Jan, Shift 2)
In the given circuit the cells have zero internal resistance. The currents (in Amperes)…JEE Main 2019 (10 Jan, Shift 1)
For the circuit shown, with R1 = 1.0 Ω, R2 = 2.0 Ω, E1 = 2 V and E2 = E3 = 4 V, the…JEE Main 2019 (8 Apr, Shift 1)