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JEE Main 2026 (6 Apr, Shift 2) · Moving Coil Galvanometer, Ammeter & Voltmeter

Moving Coil Galvanometer, Ammeter & Voltmeter question from JEE Main 2026 (6 Apr, Shift 2)

Q11JEE Main 2026 · 6 APR · SHIFT 2Medium

Moving Coil Galvanometer, Ammeter & Voltmeter

A moving coil of galvanometer when shunted with 2 Ω2\ \Omega resistance gives a full scale deflection for a current of 500 mA. When a resistance of 470 Ω470\ \Omega is connected in series it gives a full scale deflection for 10 V potential applied on it. The value of resistance of galvanometer coil is  Ω\rule{2em}{0.4pt}\ \Omega.

Numerical answer type. Work it out, then open the answer.

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Answer: 50

  1. As ammeter: IgG=(0.5−Ig)×2⇒Ig=1G+2I_g G = (0.5 - I_g) \times 2 \Rightarrow I_g = \frac{1}{G+2}.
  2. As voltmeter: Ig(G+470)=10I_g (G + 470) = 10.
  3. G+470G+2=10⇒G+470=10G+20⇒9G=450\frac{G+470}{G+2} = 10 \Rightarrow G + 470 = 10G + 20 \Rightarrow 9G = 450
  4. G=50 ΩG = 50\ \Omega
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