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JEE Main 2021 (31 Aug, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from JEE Main 2021 (31 Aug, Shift 1)

Q92JEE Main 2021 · 31 AUG · SHIFT 1Easy

Matter Waves: de Broglie Wavelength

A moving proton and electron have the same de-Broglie wavelength. If K and P denote the K.E. and momentum respectively. Then choose the correct option:

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Answer: (a)

  1. Same λ=hP\lambda = \dfrac{h}{P} gives Pp=PeP_p = P_e.
  2. K=P22mK = \dfrac{P^2}{2m} and mp>mem_p > m_e, so Kp<KeK_p < K_e.
  3. So the answer is (a) Kp<KeK_p < K_e and Pp=PeP_p = P_e.
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