A npn transistor is connected in common emitter configuration in a… | NEET 2016 (Phase 1)

Q98NEET 2016 · PHASE 1Difficult

Junction Transistor

A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 $\Omega$ is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192 $\Omega$ , the voltage gain and the power gain of the amplifier will respectively be

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Answer: (c)

Taking the given current amplification factor as $\beta = 0.96$ (as in the official solution).
Voltage gain: $A_v = \beta \dfrac{R_L}{R_i} = 0.96 \times \dfrac{800}{192} = 4$
Power gain: $A_p = \beta A_v = 0.96 \times 4 = 3.84$
So the answer is (c) 4, 3.84.

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