A nuclear reaction given by ZXA → z+1YA + - 1e0 + v represents (a) β -decay (b) γ -decay (c) fusion (d) fission

Answer: (a). The reaction is ZXA → Z+1YA + -1e⁰ + ν. A neutron changes into a proton, emitting an electron and an antineutrino; A is unchanged and Z rises by 1. This is β⁻ decay. So the answer is (a) β -decay.

A nuclear reaction given by ZXA → z+1YA + - 1e0 + v represents | NEET 2003 (AIPMT)

Q37NEET 2003 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

A nuclear reaction given by

ZXA $\rightarrow$ z+1YA + $-$ 1e0 + $\bar{v}$ represents

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Answer: (a)

The reaction is ${}_{Z}X^{A} \to {}_{Z+1}Y^{A} + {}_{-1}e^{0} + \bar{\nu}$ .
A neutron changes into a proton, emitting an electron and an antineutrino; $A$ is unchanged and $Z$ rises by 1.
This is $\beta^-$ decay.
So the answer is (a) $\beta$ -decay.

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