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JEE Main 2004 (AIEEE) · Nucleus: Composition, Size & Nuclear Force

Nucleus: Composition, Size & Nuclear Force question from JEE Main 2004 (AIEEE)

Q35JEE Main 2004 · AIEEEMedium

Nucleus: Composition, Size & Nuclear Force

A nucleus disintegrated into two nuclear parts which have their velocities in the ratio of 2:12 : 1 The ratio of their nuclear sizes will be

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Answer: (b)

  1. Momentum conservation: m1v1=m2v2⇒A1A2=v2v1=12m_1v_1 = m_2v_2 \Rightarrow \dfrac{A_1}{A_2} = \dfrac{v_2}{v_1} = \dfrac{1}{2}
  2. R∝A1/3⇒R1R2=(12)1/3R \propto A^{1/3} \Rightarrow \dfrac{R_1}{R_2} = \left(\dfrac{1}{2}\right)^{1/3}
  3. So the answer is (b) 1:21/31 : 2^{1/3}.
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