A nucleus has mass number α and radius Rα. Another nucleus has mass number β and radius Rβ. If β = 8α then Rα/Rβ is: (a) 1 (b) 2 (c) 8 (d) 0.5

Answer: (d). R ∝ A1/3, so (Rα)/(Rβ) = ((α)/(β))1/3. = (1/8)1/3 = 1/2 = 0.5 So the answer is (d) 0.5.

A nucleus has mass number α and radius Rα. Another nucleus has mass… | JEE Main 2026 (28 Jan, Shift 2)

Q3JEE Main 2026 · 28 JAN · SHIFT 2Easy

Nucleus: Composition, Size & Nuclear Force

A nucleus has mass number $\alpha$ and radius $R_{\alpha}$ . Another nucleus has mass number $\beta$ and radius $R_{\beta}$ . If $\beta = 8\alpha$ then $R_{\alpha}/R_{\beta}$ is:

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Answer: (d)

$R \propto A^{1/3}$ , so $\frac{R_\alpha}{R_\beta} = \left(\frac{\alpha}{\beta}\right)^{1/3}$ .
$= \left(\frac{1}{8}\right)^{1/3} = \frac{1}{2} = 0.5$
So the answer is (d) 0.5.

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Nucleus: Composition, Size & Nuclear Force question from JEE Main 2026 (28 Jan, Shift 2)

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