A nucleus mnX emits one α particle and two β particles. The resulting nucleus is (a) m-6n-4Z (b) m-6nZ (c) m-4nX (d) m-4n-2Y

Answer: (c). One α: m → m-4, n → n-2. Two β⁻: n-2 → n, mass number unchanged. Atomic number n again, so the same element X with mass number m-4. So the answer is (c) m-4nX.

A nucleus mnX emits one α particle and two β particles. The resulting… | NEET 2011 (AIPMT, Prelims)

Q27NEET 2011 · AIPMT · PRELIMSEasy

Radioactive Decays: Alpha, Beta, Gamma

A nucleus ${}^{m}_{n}X$ emits one $\alpha$ particle and two $\beta$ particles. The resulting nucleus is

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Answer: (c)

One $\alpha$ : $m \to m-4$ , $n \to n-2$ .
Two $\beta^-$ : $n-2 \to n$ , mass number unchanged.
Atomic number $n$ again, so the same element $X$ with mass number $m-4$ .
So the answer is (c) ${}^{m-4}_{n}X$ .

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