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NEET 1998 (AIPMT) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from NEET 1998 (AIPMT)

Q43NEET 1998 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

A nucleus nXm{}_{n}X^{m} emits one α\alpha and two β\beta particles. The resulting nucleus is

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Answer: (a)

  1. One α\alpha: mass number m→m−4m \to m-4, atomic number n→n−2n \to n-2.
  2. Two β−\beta^-: atomic number n−2→nn-2 \to n.
  3. Same atomic number nn means the same element: nXm−4{}_{n}X^{m-4} (an isotope of the parent).
  4. So the answer is (a) nXm−4{}_{n}X^{m-4}.
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