A nucleus nXm emits one α and two β particles. The resulting nucleus is (a) nXm-4 (b) n-2Ym-4 (c) n-4Zm-4 (d) none of these

Answer: (a). One α: mass number m → m-4, atomic number n → n-2. Two β⁻: atomic number n-2 → n. Same atomic number n means the same element: nXm-4 (an isotope of the parent). So the answer is (a) nXm-4.

A nucleus nXm emits one α and two β particles. The resulting nucleus… | NEET 1998 (AIPMT)

Q43NEET 1998 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

A nucleus ${}_{n}X^{m}$ emits one $\alpha$ and two $\beta$ particles. The resulting nucleus is

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Answer: (a)

One $\alpha$ : mass number $m \to m-4$ , atomic number $n \to n-2$ .
Two $\beta^-$ : atomic number $n-2 \to n$ .
Same atomic number $n$ means the same element: ${}_{n}X^{m-4}$ (an isotope of the parent).
So the answer is (a) ${}_{n}X^{m-4}$ .

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