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NEET 1996 (AIPMT) · Nucleus: Composition, Size & Nuclear Force

Nucleus: Composition, Size & Nuclear Force question from NEET 1996 (AIPMT)

Q39NEET 1996 · AIPMTMedium

Nucleus: Composition, Size & Nuclear Force

A nucleus ruptures into two nuclear parts, which have their velocity ratio equal to 2:12 : 1. What will be the ratio of their nuclear size (nuclear radius)?

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Answer: (d)

  1. Momentum is conserved from rest: m1v1=m2v2m_1 v_1 = m_2 v_2.
  2. m1m2=v2v1=12\frac{m_1}{m_2} = \frac{v_2}{v_1} = \frac{1}{2}, and A∝mA \propto m.
  3. R∝A1/3⇒R1R2=121/3R \propto A^{1/3} \Rightarrow \frac{R_1}{R_2} = \frac{1}{2^{1/3}}
  4. So the answer is (d) 1:21/31 : 2^{1/3}.
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