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Nuclear Fission & Fusion question from NEET 2021

Q20NEET 2021Easy

Nuclear Fission & Fusion

A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding per nucleon of unfragmented nuclei is 7.6MeV while that of fragments is 8.5MeV. The total gain in the Binding Energy in the process is:

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Answer: (a)

Gain in BE $= 240 \times (8.5 - 7.6)$ (total nucleons unchanged).
$= 240 \times 0.9 = 216\ \text{MeV}$
So the answer is (a) $216\ \text{MeV}$ .

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