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JEE Main 2023 (8 Apr, Shift 1) · Nuclear Fission & Fusion

Nuclear Fission & Fusion question from JEE Main 2023 (8 Apr, Shift 1)

Q16JEE Main 2023 · 8 APR · SHIFT 1Easy

Nuclear Fission & Fusion

A nucleus with mass number 242 and binding energy per nucleon as $7.6\text{ MeV}$ breaks into two fragment each with mass number 121. If each fragment nucleus has binding energy per nucleon as $8.1\text{ MeV}$ , the total gain in binding energy is _________ $\text{MeV}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 121

Gain in BE $= 242 \times (8.1 - 7.6)$ (nucleon number unchanged).
$= 242 \times 0.5 = 121\ \text{MeV}$

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