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NEET 2013 · Diffraction at a Single Slit

Diffraction at a Single Slit question from NEET 2013

Q85NEET 2013Easy

Diffraction at a Single Slit

A parallel beam of light of wavelength λ\lambda is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is

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Answer: (c)

  1. nnth minimum: path difference between edge rays asin⁡θ=nλa\sin\theta = n\lambda.
  2. Second minimum: Δ=2λ\Delta = 2\lambda, phase difference =2πλ×2λ=4π= \frac{2\pi}{\lambda}\times 2\lambda = 4\pi.
  3. So the answer is (c) 4π4\pi.
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