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NEET 2015 (AIPMT) · Energy Stored & Force between Plates

Energy Stored & Force between Plates question from NEET 2015 (AIPMT)

Q31NEET 2015 · AIPMTEasy

Energy Stored & Force between Plates

A parallel plate air capacitor has capacity C, distance of separation between plates is d and potential difference $V$ is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is

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Answer: (d)

$F = \frac{Q^2}{2\varepsilon_0 A}$ with $Q = CV$ and $\varepsilon_0 A = Cd$ .
$F = \frac{C^2V^2}{2Cd} = \frac{CV^2}{2d}$
So the answer is (d) $\frac{CV^2}{2d}$ .

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