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MHT CET 2025 (21 Apr, Shift 2) · Dielectrics

Dielectrics question from MHT CET 2025 (21 Apr, Shift 2)

Q27MHT CET 2025 · 21 APR · SHIFT 2Easy

Dielectrics

A parallel plate capacitor has plate area 50 cm250\text{ cm}^2 and plate separation 3 mm. The space between the plates is filled with a dielectric medium of thickness 1 mm and dielectric constant 4. The capacitance becomes ( ε0=\varepsilon_0 = permittivity of free space)

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Answer: (b)

  1. C=ε0Ad−t+tKC = \frac{\varepsilon_0 A}{d - t + \frac{t}{K}}, A=50×10−4=5×10−3 m2A = 50 \times 10^{-4} = 5 \times 10^{-3}\ \text{m}^2.
  2. d−t+tK=2+14=2.25d - t + \frac{t}{K} = 2 + \frac{1}{4} = 2.25 mm =2.25×10−3= 2.25 \times 10^{-3} m.
  3. C=52.25ε0=20ε09C = \frac{5}{2.25}\varepsilon_0 = \frac{20\varepsilon_0}{9}.
  4. So the answer is (b).
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