A parallel plate capacitor is charged and then isolated. If the separation between the plates is increased, which one of the following statement is NOT correct? (a) Charge remains constant after it is isolated. (b) Potential difference across the plates decreases. (c) Potential difference across the plates increases. (d) Capacitance of capacitor decreases.

Answer: (b). Isolated: Q constant, so (a) is correct. C = (ε₀ A)/(d) falls as d increases, so (d) is correct. V = Q/C increases, so (c) is correct and (b) is wrong. So the answer is (b).

A parallel plate capacitor is charged and then isolated. If the… | MHT CET 2024 (3 May, Shift 2)

Q11MHT CET 2024 · 3 MAY · SHIFT 2Easy

Energy Stored & Force between Plates

A parallel plate capacitor is charged and then isolated. If the separation between the plates is increased, which one of the following statement is NOT correct?

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Answer: (b)

Isolated: $Q$ constant, so (a) is correct.
$C = \frac{\varepsilon_0 A}{d}$ falls as $d$ increases, so (d) is correct.
$V = \frac{Q}{C}$ increases, so (c) is correct and (b) is wrong.
So the answer is (b).

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Energy Stored & Force between Plates question from MHT CET 2024 (3 May, Shift 2)

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