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JEE Main 2019 (10 Jan, Shift 1) · Dielectrics

Dielectrics question from JEE Main 2019 (10 Jan, Shift 1)

Q95JEE Main 2019 · 10 JAN · SHIFT 1Medium

Dielectrics

A parallel plate capacitor is of area 6 cm2 and a separation 3 mm. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constants K1 = 10, K2 = 12 and K3 = 14. The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be -

Figure

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Answer: (a)

  1. Each material spans the full 3 mm gap over one third of the area: parallel.
  2. Keq=K1+K2+K33=10+12+143K_{eq}=\frac{K_1+K_2+K_3}{3}=\frac{10+12+14}{3}
  3. So the answer is (a) 12.
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