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Other: Induction & Displacement Current question from NEET 2025

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Other: Induction & Displacement Current

A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant rate with time. The magnetic field arising due to displacement current is:

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Answer: (a)

  1. Constant dσ/dtd\sigma/dt gives a constant displacement current Id=ε0dΦEdtI_d = \varepsilon_0 \frac{d\Phi_E}{dt}.
  2. Inside the plates (r<Rr < R): B=μ0Idr2πR2B = \frac{\mu_0 I_d r}{2\pi R^2}, rising with rr.
  3. Outside (r>Rr > R): B=μ0Id2πrB = \frac{\mu_0 I_d}{2\pi r}, falling with rr.
  4. So BB is non-zero (except on the axis) and largest at r=Rr = R, the cylinder joining the plate edges: answer (a).
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