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JEE Main 2023 (11 Apr, Shift 1) · Charge Sharing & Loss of Energy

Charge Sharing & Loss of Energy question from JEE Main 2023 (11 Apr, Shift 1)

Q14JEE Main 2023 · 11 APR · SHIFT 1Easy

Charge Sharing & Loss of Energy

A parallel plate capacitor of capacitance 2 F2\text{ F} is charged to a potential VV, The energy stored in the capacitor is E1E_1. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is E2E_2. The ratio E2/E1E_2/E_1 is:

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Answer: (a)

  1. Charge is fixed and capacitance doubles: E=Q22CE = \frac{Q^2}{2C}.
  2. E2=Q22(2C)=E12E_2 = \frac{Q^2}{2(2C)} = \frac{E_1}{2}
  3. E2:E1=1:2E_2 : E_1 = 1 : 2, so the answer is (a).
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