A parallel plate capacitor of capacitance 'C' is connected to a… | MHT CET 2026 (19 Apr, Shift 1)

Q6MHT CET 2026 · 19 APR · SHIFT 1Medium

Charge Sharing & Loss of Energy

A parallel plate capacitor of capacitance 'C' is connected to a battery and charged to a potential 'V'. Another capacitor of capacitance ' $3C$ ' is charged to a potential ' $3V$ '. The charging battery is then disconnected and both the capacitors are connected in parallel to each other such that positive terminal of one is connected to negative terminal of the other. The final energy of the configuration is

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Answer: (c)

Charges: $Q_1 = CV$ , $Q_2 = 3C \times 3V = 9CV$ ; opposite plates joined, so net charge $= 9CV - CV = 8CV$ .
Common potential $V' = \frac{8CV}{C + 3C} = 2V$
$U = \frac{1}{2}(4C)(2V)^2 = 8CV^2$
So the answer is (c) $8.0\,CV^2$ .

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Charge Sharing & Loss of Energy question from MHT CET 2026 (19 Apr, Shift 1)

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