A parallel plate capacitor with air between the plates has… | JEE Main 2008 (AIEEE)

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Dielectrics

A parallel plate capacitor with air between the plates has capacitance of $9\text{ pF}.$ The separation between its plates is $'d'.$ The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant $k_1 = 3$ and thickness $\frac{d}{3}$ while the other one has dielectric constant $k_2 = 6$ and thickness $\frac{2d}{3}$ . Capacitance of the capacitor is now

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Answer: (c)

Layers in series: $C=\frac{\epsilon_0A}{\frac{d}{9}+\frac{2d}{18}}=\frac{9}{2}\cdot\frac{\epsilon_0A}{d}$
$C=4.5\times9=40.5\text{ pF}$
So the answer is (c) 40.5 pF.

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Dielectrics question from JEE Main 2008 (AIEEE)

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