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JEE Main 2023 (24 Jan, Shift 2) · Dielectrics

Dielectrics question from JEE Main 2023 (24 Jan, Shift 2)

Q50JEE Main 2023 · 24 JAN · SHIFT 2Easy

Dielectrics

A parallel plate capacitor with air between the plates has a capacitance of 15pF. The separation between the plates becomes twice and the space between them is filled with a medium of dielectric constant 3.5. Then the capacitance becomes $\frac{x}{4}$ pF. The value of $x$ is ____________.

Numerical answer type. Work it out, then open the answer.

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Answer: 105

$C = \frac{K\varepsilon_0 A}{d}$ , so $C' = C \times \frac{K}{2}$ when $d$ doubles.
$C' = 15 \times \frac{3.5}{2} = 26.25$ pF $= \frac{105}{4}$ pF.
So $x = 105$ .

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