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JEE Main 2021 (25 Jul, Shift 1) · Dielectrics

Dielectrics question from JEE Main 2021 (25 Jul, Shift 1)

Q86JEE Main 2021 · 25 JUL · SHIFT 1Difficult

Dielectrics

A parallel plate capacitor with plate area 'A' and distance of separation 'd' is filled with a dielectric. What is the capacity of the capacitor when permittivity of the dielectric varies as: ε(x)=ε0+kx\varepsilon(x) = \varepsilon_0 + kx, for (0<x≤d2)\left(0 < x \le \frac{d}{2}\right)

ε(x)=ε0+k(d−x)\varepsilon(x) = \varepsilon_0 + k(d-x), for (d2≤x≤d)\left(\frac{d}{2} \le x \le d\right)

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Answer: (b)

  1. Layers in series: 1C=∫0ddxε(x)A\frac{1}{C} = \int_0^d \frac{dx}{\varepsilon(x) A}; by symmetry, twice the first half.
  2. 1C=2A∫0d/2dxε0+kx=2kAln⁡(2ε0+kd2ε0)\frac{1}{C} = \frac{2}{A}\int_0^{d/2} \frac{dx}{\varepsilon_0 + kx} = \frac{2}{kA}\ln\left(\frac{2\varepsilon_0 + kd}{2\varepsilon_0}\right)
  3. C=kA2ln⁡(2ε0+kd2ε0)C = \frac{kA}{2\ln\left(\frac{2\varepsilon_0 + kd}{2\varepsilon_0}\right)}, so the answer is (b).
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