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JEE Main 2022 (26 Jun, Shift 2) · Dielectrics

Dielectrics question from JEE Main 2022 (26 Jun, Shift 2)

Q65JEE Main 2022 · 26 JUN · SHIFT 2Medium

Dielectrics

A parallel plate capacitor with plate area A and plate separation d = 2 m has a capacitance of 4 $\mu$ F. The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K = 3 (as shown in figure) will be:

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Answer: (c)

Slab fills half the gap ( $\frac{d}{2}$ ) over the full area: series with air.
$C=\frac{\epsilon_0A}{\frac{d}{2}+\frac{d}{6}}=\frac{3}{2}\cdot\frac{\epsilon_0A}{d}=1.5\times4$
So the answer is (c) $6\ \mu\text{F}$ .

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