A paramagnetic material has 1028 atoms/m3. Its magnetic susceptibility at temperature 350 K is 2.8 × 10–4. Its susceptibility at 300 K is: (a) 3.726 × 10−4 (b) 2.672 × 10−4 (c) 3.672 × 10−4 (d) 3.267 × 10 - 4

Answer: (d). Curie's law: χ ∝ 1/T, so χ₂ = χ₁ (T₁)/(T₂). The number of atoms per m³ is not needed. χ₂ = 2.8 × 10⁻⁴ × (350)/(300) χ₂ = 3.267 × 10⁻⁴ So the answer is (d) 3.267 × 10⁻⁴.

A paramagnetic material has 1028 atoms/m3. Its magnetic… | JEE Main 2019 (12 Jan, Shift 2)

Q28JEE Main 2019 · 12 JAN · SHIFT 2Medium

Magnetic Materials & Curie Law

A paramagnetic material has 1028 atoms/m3. Its magnetic susceptibility at temperature 350 K is 2.8 $\times$ 10–4. Its susceptibility at 300 K is:

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Answer: (d)

Curie's law: $\chi \propto \dfrac{1}{T}$ , so $\chi_2 = \chi_1 \dfrac{T_1}{T_2}$ . The number of atoms per $\text{m}^3$ is not needed.
$\chi_2 = 2.8 \times 10^{-4} \times \dfrac{350}{300}$
$\chi_2 = 3.267 \times 10^{-4}$
So the answer is (d) $3.267 \times 10^{-4}$ .

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