A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 × 10−6 J/ T when a magnetic intensity of 60 × 103 A/m is applied. Its magnetic susceptibility is (a) 3.3 × 10−4 (b) 2.3 × 10−2 (c) 4.3 × 10−2 (d) 3.3 × 10−2

Answer: (a). M = m/V = 20 × 10⁻⁶10⁻⁶ = 20 A m⁻¹ χ = M/H = 2060 × 10³ = 3.3 × 10⁻⁴ So the answer is (a) 3.3 × 10⁻⁴.

A paramagnetic substance in the form of a cube with sides 1 cm has a… | JEE Main 2019 (11 Jan, Shift 2)

Q45JEE Main 2019 · 11 JAN · SHIFT 2Medium

Magnetisation: B, H, M, χ & μ

A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 $\times$ 10−6 J/ T when a magnetic intensity of 60 $\times$ 103 A/m is applied. Its magnetic susceptibility is

Show answer and solution

Answer: (a)

$M = \dfrac{m}{V} = \dfrac{20 \times 10^{-6}}{10^{-6}} = 20\ \text{A m}^{-1}$
$\chi = \dfrac{M}{H} = \dfrac{20}{60 \times 10^{3}} = 3.3 \times 10^{-4}$
So the answer is (a) $3.3 \times 10^{-4}$ .

Report a mistake

Magnetisation: B, H, M, χ & μ question from JEE Main 2019 (11 Jan, Shift 2)

More questions on Magnetisation: B, H, M, χ & μ