A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment 20 × 10⁻⁶ J/T when a magnetic intensity 60 × 10³ A/m is applied. Its magnetic susceptibility is (a) 3.3 × 10⁻⁴ (b) 3.3 × 10⁻² (c) 4.3 × 10⁻² (d) 2.3 × 10⁻²

Answer: (a). Magnetisation M = m/V = 20 × 10⁻⁶(10⁻²)³ = 20 A m⁻¹ Susceptibility χ = M/H = 2060 × 10³ = 3.3 × 10⁻⁴ So the answer is (a) 3.3 × 10⁻⁴.

A paramagnetic substance in the form of a cube with sides 1 cm has a… | MHT CET 2026 (14 May, Shift 2)

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Magnetisation: B, H, M, χ & μ

A paramagnetic substance in the form of a cube with sides $1$ cm has a magnetic dipole moment $20 \times 10^{-6}$ J/T when a magnetic intensity $60 \times 10^{3}$ A/m is applied. Its magnetic susceptibility is

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Answer: (a)

Magnetisation $M = \dfrac{m}{V} = \dfrac{20 \times 10^{-6}}{(10^{-2})^3} = 20\ \text{A m}^{-1}$
Susceptibility $\chi = \dfrac{M}{H} = \dfrac{20}{60 \times 10^{3}} = 3.3 \times 10^{-4}$
So the answer is (a) $3.3 \times 10^{-4}$ .

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Magnetisation: B, H, M, χ & μ question from MHT CET 2026 (14 May, Shift 2)

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