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MHT CET 2021 (20 Sep, Shift 2) · Non-Uniform Circular Motion

Non-Uniform Circular Motion question from MHT CET 2021 (20 Sep, Shift 2)

Q16MHT CET 2021 · 20 SEP · SHIFT 2Medium

Non-Uniform Circular Motion

A particle at rest starts moving with a constant angular acceleration of $4\text{ rad/s}^2$ in a circular path. At what time the magnitude of its centripetal acceleration and tangential acceleration will be equal?

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Answer: (c)

From rest: $a_c = \omega^2 r = \alpha^2 t^2 r$ , $a_t = \alpha r$
Equal: $t = \frac{1}{\sqrt{\alpha}} = \frac{1}{\sqrt{4}} = \frac{1}{2}$ s
So the answer is (c) $\frac{1}{2}\text{ s}$ .

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