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MHT CET 2025 (23 Apr, Shift 2) · Conical Pendulum & Funnel

Conical Pendulum & Funnel question from MHT CET 2025 (23 Apr, Shift 2)

Q4MHT CET 2025 · 23 APR · SHIFT 2Easy

Conical Pendulum & Funnel

A particle describes a horizontal circle on smooth inner surface of a cone as shown in figure. If the height of the circle above the vertex is 10 cm. The speed of the particle is (g(g, acceleration due to gravity =10 m/s2)= 10\text{ m/s}^2)

Figure

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Answer: (c)

  1. For a particle on the smooth inner surface of a cone, h=v2gh = \frac{v^2}{g}.
  2. v=gh=10×0.1v = \sqrt{gh} = \sqrt{10 \times 0.1}
  3. v=1v = 1 m/s
  4. So the answer is (c) 1 m/s.
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